regsub: fix substitution with a trailing backslash

Should just replace with the bare backslash, not backslash '\0'

Signed-off-by: Steve Bennett <steveb@workware.net.au>

1 files changed, 4 insertions, 1 deletions

diff --git a/jim-regexp.c b/jim-regexp.c
index 25ffd21..25e05a3 100644
--- a/jim-regexp.c
+++ b/jim-regexp.c
@@ -496,7 +496,10 @@ int Jim_RegsubCmd(Jim_Interp *interp, int argc, Jim_Obj *const *argv)
                     continue;
                 }
                 else {
-                    Jim_AppendString(interp, resultObj, replace_str + j - 1, 2);
+                    /* If the replacement is a trailing backslash, just replace with a backslash, otherwise
+                     * with the literal backslash and the following character
+                     */
+                    Jim_AppendString(interp, resultObj, replace_str + j - 1, (j == replace_len) ? 1 : 2);
                     continue;
                 }
             }