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authorAlberto Garcia <berto@igalia.com>2015-02-05 14:55:31 +0200
committerKevin Wolf <kwolf@redhat.com>2015-02-06 17:24:22 +0100
commit8e8cb375e0964b4ed099cb8563029028db26a834 (patch)
tree6a9778b60835d3f49535d634dc753a1c173f4c78 /block
parentfa21e6faa6f1d7de49fd030ebdb0722b59cf9a41 (diff)
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block: Give always priority to unused entries in the qcow2 L2 cache
The current algorithm to replace entries from the L2 cache gives priority to newer hits by dividing the hit count of all existing entries by two everytime there is a cache miss. However, if there are several cache misses the hit count of the existing entries can easily go down to 0. This will result in those entries being replaced even when there are others that have never been used. This problem is more noticeable with larger disk images and cache sizes, since the chances of having several misses before the cache is full are higher. If we make sure that the hit count can never go down to 0 again, unused entries will always have priority. Signed-off-by: Alberto Garcia <berto@igalia.com> Reviewed-by: Max Reitz <mreitz@redhat.com> Signed-off-by: Kevin Wolf <kwolf@redhat.com>
Diffstat (limited to 'block')
-rw-r--r--block/qcow2-cache.c4
1 files changed, 3 insertions, 1 deletions
diff --git a/block/qcow2-cache.c b/block/qcow2-cache.c
index 904f6b1..b115549 100644
--- a/block/qcow2-cache.c
+++ b/block/qcow2-cache.c
@@ -253,7 +253,9 @@ static int qcow2_cache_find_entry_to_replace(Qcow2Cache *c)
/* Give newer hits priority */
/* TODO Check how to optimize the replacement strategy */
- c->entries[i].cache_hits /= 2;
+ if (c->entries[i].cache_hits > 1) {
+ c->entries[i].cache_hits /= 2;
+ }
}
if (min_index == -1) {