Remove special Hexagon packet traversal code

On Hexagon, breakpoints need to be on the first instruction of a packet.
When the LLVM disassembler for Hexagon returned 32 bit instructions, we
needed code to find the start of the current packet. Now that the LLVM
disassembler for Hexagon returns packets instead of instructions, we always
have the first instruction of the packet. Remove the packet traversal code
because it can cause problems when the next packet has more than one
instruction.

Reviewed By: clayborg

Differential Revision: https://reviews.llvm.org/D84966

1 files changed, 2 insertions, 6 deletions

diff --git a/lldb/source/Target/ThreadPlanStepRange.cpp b/lldb/source/Target/ThreadPlanStepRange.cpp
index f4b2ee3..3c42cd7 100644
--- a/lldb/source/Target/ThreadPlanStepRange.cpp
+++ b/lldb/source/Target/ThreadPlanStepRange.cpp
@@ -327,13 +327,9 @@ bool ThreadPlanStepRange::SetNextBranchBreakpoint() {
   if (instructions == nullptr)
     return false;
   else {
-    Target &target = GetThread().GetProcess()->GetTarget();
     const bool ignore_calls = GetKind() == eKindStepOverRange;
-    uint32_t branch_index =
-        instructions->GetIndexOfNextBranchInstruction(pc_index, target,
-                                                      ignore_calls, 
-                                                      &m_found_calls);
-
+    uint32_t branch_index = instructions->GetIndexOfNextBranchInstruction(
+        pc_index, ignore_calls, &m_found_calls);
     Address run_to_address;
 
     // If we didn't find a branch, run to the end of the range.