re PR fortran/25078 (EQUILALENCE requires two or more objects)

        PR fortran/25078
        * match.c (gfc_match_equivalence):  Count number of objects.

        gfortran.dg/equiv_5.f90:  New test.

From-SVN: r108426

1 files changed, 12 insertions, 0 deletions

diff --git a/gcc/fortran/match.c b/gcc/fortran/match.c
index 8ca7ed6..fd4fe33 100644
--- a/gcc/fortran/match.c
+++ b/gcc/fortran/match.c
@@ -2599,6 +2599,7 @@ gfc_match_equivalence (void)
   match m;
   gfc_common_head *common_head = NULL;
   bool common_flag;
+  int cnt;
 
   tail = NULL;
 
@@ -2616,6 +2617,7 @@ gfc_match_equivalence (void)
 
       set = eq;
       common_flag = FALSE;
+      cnt = 0;
 
       for (;;)
 	{
@@ -2625,6 +2627,9 @@ gfc_match_equivalence (void)
 	  if (m == MATCH_NO)
 	    goto syntax;
 
+	  /*  count the number of objects.  */
+	  cnt++;
+
 	  if (gfc_match_char ('%') == MATCH_YES)
 	    {
 	      gfc_error ("Derived type component %C is not a "
@@ -2655,6 +2660,7 @@ gfc_match_equivalence (void)
 
 	  if (gfc_match_char (')') == MATCH_YES)
 	    break;
+
 	  if (gfc_match_char (',') != MATCH_YES)
 	    goto syntax;
 
@@ -2662,6 +2668,12 @@ gfc_match_equivalence (void)
 	  set = set->eq;
 	}
 
+      if (cnt < 2)
+	{
+	  gfc_error ("EQUIVALENCE at %C requires two or more objects");
+	  goto cleanup;
+	}
+
       /* If one of the members of an equivalence is in common, then
 	 mark them all as being in common.  Before doing this, check
 	 that members of the equivalence group are not in different