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/* This testcase is part of GDB, the GNU debugger.
Copyright 2015-2024 Free Software Foundation, Inc.
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>. */
/*
Define TestStrings, TestStringsH, and TestStringsW to test utf8, utf16,
and utf32 strings respectively.
To avoid compile errors due to old compiler mode, we don't use string
literals. The content of each array is the same as followings:
const char TestStrings[] = {
"ABCD"
"EFGHIJKLMNOPQRSTUVWXYZ\0"
"\0"
"\0"
"\u307B\u3052\u307B\u3052\0"
"012345678901234567890123456789\0"
"!!!!!!\0"
};
*/
unsigned char TestStringsBase[] = {
/* This is here just to ensure we have a null character before
TestStrings, to avoid showing garbage when we look for strings
backwards from TestStrings. */
0x0,
0x41, 0x42, 0x43, 0x44, 0x45, 0x46, 0x47, 0x48,
0x49, 0x4a, 0x4b, 0x4c, 0x4d, 0x4e, 0x4f, 0x50,
0x51, 0x52, 0x53, 0x54, 0x55, 0x56, 0x57, 0x58,
0x59, 0x5a, 0x00, 0x00, 0x00, 0xe3, 0x81, 0xbb,
0xe3, 0x81, 0x92, 0xe3, 0x81, 0xbb, 0xe3, 0x81,
0x92, 0x00, 0x30, 0x31, 0x32, 0x33, 0x34, 0x35,
0x36, 0x37, 0x38, 0x39, 0x30, 0x31, 0x32, 0x33,
0x34, 0x35, 0x36, 0x37, 0x38, 0x39, 0x30, 0x31,
0x32, 0x33, 0x34, 0x35, 0x36, 0x37, 0x38, 0x39,
0x00, 0x21, 0x21, 0x21, 0x21, 0x21, 0x21, 0x00,
0x00
};
unsigned char *TestStrings = &TestStringsBase[1];
short TestStringsHBase[] = {
/* This is here just to ensure we have a null character before
TestStringsH, to avoid showing garbage when we look for strings
backwards from TestStringsH. */
0x0,
0x0041, 0x0042, 0x0043, 0x0044, 0x0045, 0x0046, 0x0047, 0x0048,
0x0049, 0x004a, 0x004b, 0x004c, 0x004d, 0x004e, 0x004f, 0x0050,
0x0051, 0x0052, 0x0053, 0x0054, 0x0055, 0x0056, 0x0057, 0x0058,
0x0059, 0x005a, 0x0000, 0x0000, 0x0000, 0x307b, 0x3052, 0x307b,
0x3052, 0x0000, 0x0030, 0x0031, 0x0032, 0x0033, 0x0034, 0x0035,
0x0036, 0x0037, 0x0038, 0x0039, 0x0030, 0x0031, 0x0032, 0x0033,
0x0034, 0x0035, 0x0036, 0x0037, 0x0038, 0x0039, 0x0030, 0x0031,
0x0032, 0x0033, 0x0034, 0x0035, 0x0036, 0x0037, 0x0038, 0x0039,
0x0000, 0x0021, 0x0021, 0x0021, 0x0021, 0x0021, 0x0021, 0x0000,
0x0000
};
short *TestStringsH = &TestStringsHBase[1];
int TestStringsWBase[] = {
/* This is here just to ensure we have a null character before
TestStringsW, to avoid showing garbage when we look for strings
backwards from TestStringsW. */
0x0,
0x00000041, 0x00000042, 0x00000043, 0x00000044,
0x00000045, 0x00000046, 0x00000047, 0x00000048,
0x00000049, 0x0000004a, 0x0000004b, 0x0000004c,
0x0000004d, 0x0000004e, 0x0000004f, 0x00000050,
0x00000051, 0x00000052, 0x00000053, 0x00000054,
0x00000055, 0x00000056, 0x00000057, 0x00000058,
0x00000059, 0x0000005a, 0x00000000, 0x00000000,
0x00000000, 0x0000307b, 0x00003052, 0x0000307b,
0x00003052, 0x00000000, 0x00000030, 0x00000031,
0x00000032, 0x00000033, 0x00000034, 0x00000035,
0x00000036, 0x00000037, 0x00000038, 0x00000039,
0x00000030, 0x00000031, 0x00000032, 0x00000033,
0x00000034, 0x00000035, 0x00000036, 0x00000037,
0x00000038, 0x00000039, 0x00000030, 0x00000031,
0x00000032, 0x00000033, 0x00000034, 0x00000035,
0x00000036, 0x00000037, 0x00000038, 0x00000039,
0x00000000, 0x00000021, 0x00000021, 0x00000021,
0x00000021, 0x00000021, 0x00000021, 0x00000000,
0x00000000
};
int *TestStringsW = &TestStringsWBase[1];
int
main (void)
{
/* Clang++ eliminates the variables if nothing references them. */
int dummy = TestStrings[0] + TestStringsH[0] + TestStringsW[0];
/* Backward disassemble test requires at least 20 instructions in
this function. Adding a simple bubble sort. */
int i, j;
int n[] = {3, 1, 4, 1, 5, 9};
int len = sizeof (n) / sizeof (n[0]);
for (i = 0; i < len - 1; ++i)
{
for (j = i; j < len; ++j)
{
if (n[j] < n[i])
{
int tmp = n[i];
n[i] = n[j];
n[j] = tmp;
}
}
}
return 42;
}
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