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author | Vladimir Sementsov-Ogievskiy <vsementsov@virtuozzo.com> | 2021-04-28 18:17:37 +0300 |
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committer | Kevin Wolf <kwolf@redhat.com> | 2021-04-30 12:27:48 +0200 |
commit | 3bf416ba0fdc0667e34ef912fbe1074ad259f533 (patch) | |
tree | d2ccc13c0e1e6a93a16b46a03be140a6a4dd47ac /block.c | |
parent | 8cad15b1561ee6a1dd473d3f03c982b4dde574a3 (diff) | |
download | qemu-3bf416ba0fdc0667e34ef912fbe1074ad259f533.zip qemu-3bf416ba0fdc0667e34ef912fbe1074ad259f533.tar.gz qemu-3bf416ba0fdc0667e34ef912fbe1074ad259f533.tar.bz2 |
block: bdrv_refresh_perms: check for parents permissions conflict
Add additional check that node parents do not interfere with each
other. This should not hurt existing callers and allows in further
patch use bdrv_refresh_perms() to update a subtree of changed
BdrvChild (check that change is correct).
New check will substitute bdrv_check_update_perm() in following
permissions refactoring, so keep error messages the same to avoid
unit test result changes.
Signed-off-by: Vladimir Sementsov-Ogievskiy <vsementsov@virtuozzo.com>
Reviewed-by: Alberto Garcia <berto@igalia.com>
Reviewed-by: Kevin Wolf <kwolf@redhat.com>
Message-Id: <20210428151804.439460-10-vsementsov@virtuozzo.com>
Signed-off-by: Kevin Wolf <kwolf@redhat.com>
Diffstat (limited to 'block.c')
-rw-r--r-- | block.c | 63 |
1 files changed, 54 insertions, 9 deletions
@@ -2026,6 +2026,57 @@ bool bdrv_is_writable(BlockDriverState *bs) return bdrv_is_writable_after_reopen(bs, NULL); } +static char *bdrv_child_user_desc(BdrvChild *c) +{ + if (c->klass->get_parent_desc) { + return c->klass->get_parent_desc(c); + } + + return g_strdup("another user"); +} + +static bool bdrv_a_allow_b(BdrvChild *a, BdrvChild *b, Error **errp) +{ + g_autofree char *user = NULL; + g_autofree char *perm_names = NULL; + + if ((b->perm & a->shared_perm) == b->perm) { + return true; + } + + perm_names = bdrv_perm_names(b->perm & ~a->shared_perm); + user = bdrv_child_user_desc(a); + error_setg(errp, "Conflicts with use by %s as '%s', which does not " + "allow '%s' on %s", + user, a->name, perm_names, bdrv_get_node_name(b->bs)); + + return false; +} + +static bool bdrv_parent_perms_conflict(BlockDriverState *bs, Error **errp) +{ + BdrvChild *a, *b; + + /* + * During the loop we'll look at each pair twice. That's correct because + * bdrv_a_allow_b() is asymmetric and we should check each pair in both + * directions. + */ + QLIST_FOREACH(a, &bs->parents, next_parent) { + QLIST_FOREACH(b, &bs->parents, next_parent) { + if (a == b) { + continue; + } + + if (!bdrv_a_allow_b(a, b, errp)) { + return true; + } + } + } + + return false; +} + static void bdrv_child_perm(BlockDriverState *bs, BlockDriverState *child_bs, BdrvChild *c, BdrvChildRole role, BlockReopenQueue *reopen_queue, @@ -2203,15 +2254,6 @@ void bdrv_get_cumulative_perm(BlockDriverState *bs, uint64_t *perm, *shared_perm = cumulative_shared_perms; } -static char *bdrv_child_user_desc(BdrvChild *c) -{ - if (c->klass->get_parent_desc) { - return c->klass->get_parent_desc(c); - } - - return g_strdup("another user"); -} - char *bdrv_perm_names(uint64_t perm) { struct perm_name { @@ -2355,6 +2397,9 @@ static int bdrv_refresh_perms(BlockDriverState *bs, Error **errp) int ret; uint64_t perm, shared_perm; + if (bdrv_parent_perms_conflict(bs, errp)) { + return -EPERM; + } bdrv_get_cumulative_perm(bs, &perm, &shared_perm); ret = bdrv_check_perm(bs, NULL, perm, shared_perm, NULL, errp); if (ret < 0) { |