From 688121571ae35f2f767ae16aa84c8df4a889ab72 Mon Sep 17 00:00:00 2001
From: Rafael Espindola <rafael.espindola@gmail.com>
Date: Wed, 3 Sep 2014 17:31:46 +0000
Subject: Pass a && to getLazyBitcodeModule.

This forces callers to use std::move when calling it. It is somewhat odd to have
code with std::move that doesn't always move, but it is also odd to have code
without std::move that sometimes moves.

llvm-svn: 217049
---
 llvm/unittests/Bitcode/BitReaderTest.cpp | 3 ++-
 1 file changed, 2 insertions(+), 1 deletion(-)

(limited to 'llvm/unittests/Bitcode/BitReaderTest.cpp')

diff --git a/llvm/unittests/Bitcode/BitReaderTest.cpp b/llvm/unittests/Bitcode/BitReaderTest.cpp
index eb6c125..a27332b 100644
--- a/llvm/unittests/Bitcode/BitReaderTest.cpp
+++ b/llvm/unittests/Bitcode/BitReaderTest.cpp
@@ -53,7 +53,8 @@ static std::unique_ptr<Module> getLazyModuleFromAssembly(LLVMContext &Context,
   writeModuleToBuffer(parseAssembly(Assembly), Mem);
   std::unique_ptr<MemoryBuffer> Buffer =
       MemoryBuffer::getMemBuffer(Mem.str(), "test", false);
-  ErrorOr<Module *> ModuleOrErr = getLazyBitcodeModule(Buffer, Context);
+  ErrorOr<Module *> ModuleOrErr =
+      getLazyBitcodeModule(std::move(Buffer), Context);
   return std::unique_ptr<Module>(ModuleOrErr.get());
 }
 
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