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author | Shahab Vahedi <shahab@synopsys.com> | 2022-11-27 18:38:24 +0100 |
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committer | Vineet Gupta <vineet.gupta@linux.dev> | 2022-11-29 14:33:56 -0800 |
commit | 987f8647e8d6206cebc613e5c162ff8b4d014d40 (patch) | |
tree | 6ca53f8e72e18c0779826d4cbb3c2671f36a5db4 /support | |
parent | 227df6243a2b5b4d70d11772d12c02eb9cb666ca (diff) | |
download | glibc-987f8647e8d6206cebc613e5c162ff8b4d014d40.zip glibc-987f8647e8d6206cebc613e5c162ff8b4d014d40.tar.gz glibc-987f8647e8d6206cebc613e5c162ff8b4d014d40.tar.bz2 |
scripts: Add "|" operator support to glibcpp's parsing
From the tests point of view, this is a necessary step for another
patch [1] and allows parsing macros such as "#define A | B". Without
it, a few tests [2] choke when the other patch [1] is applied:
/src/glibc/scripts/../elf/elf.h:4167: error: uninterpretable macro
token sequence: ( EF_ARC_MACH_MSK | EF_ARC_OSABI_MSK )
Traceback (most recent call last):
File "/src/glibc/elf/tst-glibcelf.py", line 23, in <module>
import glibcelf
File "/src/glibc/scripts/glibcelf.py", line 226, in <module>
_elf_h = _parse_elf_h()
^^^^^^^^^^^^^^
File "/src/glibc/scripts/glibcelf.py", line 223, in _parse_elf_h
raise IOError('parse error in elf.h')
OSError: parse error in elf.h
[1] ARC: update definitions in elf/elf.h
https://sourceware.org/pipermail/libc-alpha/2022-November/143503.html
[2]
tst-glibcelf, tst-relro-ldso, and tst-relro-libc
Reviewed-by: Florian Weimer <fweimer@redhat.com>
Signed-off-by: Shahab Vahedi <shahab@synopsys.com>
Diffstat (limited to 'support')
-rw-r--r-- | support/tst-glibcpp.py | 1 |
1 files changed, 1 insertions, 0 deletions
diff --git a/support/tst-glibcpp.py b/support/tst-glibcpp.py index a2db191..cca8bd6 100644 --- a/support/tst-glibcpp.py +++ b/support/tst-glibcpp.py @@ -131,6 +131,7 @@ check_macro_eval('#define A 1', {'A': 1}) check_macro_eval('#define A (1)', {'A': 1}) check_macro_eval('#define A (1 + 1)', {'A': 2}) check_macro_eval('#define A (1U << 31)', {'A': 1 << 31}) +check_macro_eval('#define A (1 | 2)', {'A': 1 | 2}) check_macro_eval('''\ #define A (B + 1) #define B 10 |