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authorJoseph Myers <joseph@codesourcery.com>2021-09-17 19:24:14 +0000
committerJoseph Myers <joseph@codesourcery.com>2021-09-17 19:24:14 +0000
commit885762aa31d75de8b9fea4c0e2e372b582d4c548 (patch)
tree183f1aa52c8c1bca2297768a1750fa70e1126891 /NEWS
parentf3eef963902d0f54f68cffc74f79b97f4d6154b7 (diff)
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Use $(pie-default) with conformtest
My glibc bot showed that my conformtest changes fail the build of the conformtest execution tests for x86_64-linux-gnu-static-pie, because linking the newly built object with the newly built libc and the associated options normally used for linking requires it to be built as PIE. Add $(pie-default) to the compiler command used so that PIE options are used when required. There's a case for using the whole of $(CFLAGS-.o) (which includes $(pie-default)), but that raises questions of any impact from using optimization flags from CFLAGS in these tests. So for now just use $(pie-default) as the key part of $(CFLAGS-.o) that's definitely needed. Tested with build-many-glibcs.py for x86_64-linux-gnu-static-pie.
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