/* This testcase is part of GDB, the GNU debugger.
Copyright 2010-2022 Free Software Foundation, Inc.
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see . */
/* This program tests tracepoint speed. It consists of two identical
loops, which in normal execution will run for exactly the same
amount of time. A tracepoint in the second loop will slow it down
by some amount, and then the program will report the slowdown
observed. */
/* While primarily designed for the testsuite, it can also be used
for interactive testing. */
#include
#include
#include
#include
#include
int trace_speed_test (void);
/* We mark these globals as volatile so the speed-measuring loops
don't get totally emptied out at high optimization levels. */
volatile int globfoo, globfoo2, globfoo3;
volatile short globarr[80000];
int init_iters = 10 * 1000;
int iters;
int max_iters = 1000 * 1000 * 1000;
int numtps = 1;
unsigned long long now2, now3, now4, now5;
int total1, total2, idelta, mindelta, nsdelta;
int nspertp = 0;
/* Return CPU usage (both user and system - trap-based tracepoints use
a bunch of system time). */
unsigned long long
myclock ()
{
struct timeval tm;
gettimeofday (&tm, NULL);
return (((unsigned long long) tm.tv_sec) * 1000000) + tm.tv_usec;
}
int
main(int argc, char **argv)
{
int problem;
iters = init_iters;
while (1)
{
numtps = 1; /* set pre-run breakpoint here */
/* Keep trying the speed test, with more iterations, until
we get to a reasonable number. */
while ((problem = trace_speed_test()))
{
/* If iteration isn't working, give up. */
if (iters > max_iters)
{
printf ("Gone over %d iterations, giving up\n", max_iters);
break;
}
if (problem < 0)
{
printf ("Negative times, giving up\n");
break;
}
iters *= 2;
printf ("Doubled iterations to %d\n", iters);
}
printf ("Tracepoint time is %d ns\n", nspertp);
/* This is for the benefit of interactive testing and attaching,
keeps the program from pegging the machine. */
sleep (1); /* set post-run breakpoint here */
/* Issue a little bit of output periodically, so we can see if
program is alive or hung. */
printf ("%s keeping busy, clock=%llu\n", argv[0], myclock ());
}
return 0;
}
int
trace_speed_test (void)
{
int i;
/* Overall loop run time deltas under 1 ms are likely noise and
should be ignored. */
mindelta = 1000;
// The bodies of the two loops following must be identical.
now2 = myclock ();
globfoo2 = 1;
for (i = 0; i < iters; ++i)
{
globfoo2 *= 45;
globfoo2 += globfoo + globfoo3;
globfoo2 *= globfoo + globfoo3;
globfoo2 -= globarr[4] + globfoo3;
globfoo2 *= globfoo + globfoo3;
globfoo2 += globfoo + globfoo3;
}
now3 = myclock ();
total1 = now3 - now2;
now4 = myclock ();
globfoo2 = 1;
for (i = 0; i < iters; ++i)
{
globfoo2 *= 45;
globfoo2 += globfoo + globfoo3; /* set tracepoint here */
globfoo2 *= globfoo + globfoo3;
globfoo2 -= globarr[4] + globfoo3;
globfoo2 *= globfoo + globfoo3;
globfoo2 += globfoo + globfoo3;
}
now5 = myclock ();
total2 = now5 - now4;
/* Report on the test results. */
nspertp = 0;
idelta = total2 - total1;
printf ("Loops took %d usec and %d usec, delta is %d usec, %d iterations\n",
total1, total2, idelta, iters);
/* If the second loop seems to run faster, things are weird so give up. */
if (idelta < 0)
return -1;
if (idelta > mindelta
/* Total test time should be between 15 and 30 seconds. */
&& (total1 + total2) > (15 * 1000000)
&& (total1 + total2) < (30 * 1000000))
{
nsdelta = (((unsigned long long) idelta) * 1000) / iters;
printf ("Second loop took %d ns longer per iter than first\n", nsdelta);
nspertp = nsdelta / numtps;
printf ("%d ns per tracepoint\n", nspertp);
printf ("Base iteration time %d ns\n",
((int) (((unsigned long long) total1) * 1000) / iters));
printf ("Total test time %d secs\n", ((int) ((now5 - now2) / 1000000)));
/* Speed test ran with no problem. */
return 0;
}
/* The test run was too brief, or otherwise not useful. */
return 1;
}