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authorDJ Delorie <dj@redhat.com>2006-04-12 18:42:01 +0000
committerDJ Delorie <dj@redhat.com>2006-04-12 18:42:01 +0000
commit3db2e6ddf680eecc3060ba5a12d4c97072389d90 (patch)
treeab8a75ac527440e6f89d20b23afc619aa09d188c /include
parent01d3a6ce134b69233591c6ad34ecdf844142e2c4 (diff)
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merge from gcc
Diffstat (limited to 'include')
-rw-r--r--include/ChangeLog4
-rw-r--r--include/libiberty.h41
2 files changed, 45 insertions, 0 deletions
diff --git a/include/ChangeLog b/include/ChangeLog
index af4eb6d..0a3787a 100644
--- a/include/ChangeLog
+++ b/include/ChangeLog
@@ -1,3 +1,7 @@
+2006-04-11 Jim Blandy <jimb@codesourcery.com>
+
+ * libiberty.h (pex_input_file, pex_input_pipe): New declarations.
+
2006-04-06 H.J. Lu <hongjiu.lu@intel.com>
* bfdlink.h (bfd_link_info): Replace need_relax_finalize with
diff --git a/include/libiberty.h b/include/libiberty.h
index c264cb2..6bd318e 100644
--- a/include/libiberty.h
+++ b/include/libiberty.h
@@ -448,6 +448,47 @@ extern const char *pex_run (struct pex_obj *obj, int flags,
const char *outname, const char *errname,
int *err);
+/* Return a `FILE' pointer FP for the standard input of the first
+ program in the pipeline; FP is opened for writing. You must have
+ passed `PEX_USE_PIPES' to the `pex_init' call that returned OBJ.
+ You must close FP yourself with `fclose' to indicate that the
+ pipeline's input is complete.
+
+ The file descriptor underlying FP is marked not to be inherited by
+ child processes.
+
+ This call is not supported on systems which do not support pipes;
+ it returns with an error. (We could implement it by writing a
+ temporary file, but then you would need to write all your data and
+ close FP before your first call to `pex_run' -- and that wouldn't
+ work on systems that do support pipes: the pipe would fill up, and
+ you would block. So there isn't any easy way to conceal the
+ differences between the two types of systems.)
+
+ If you call both `pex_write_input' and `pex_read_output', be
+ careful to avoid deadlock. If the output pipe fills up, so that
+ each program in the pipeline is waiting for the next to read more
+ data, and you fill the input pipe by writing more data to FP, then
+ there is no way to make progress: the only process that could read
+ data from the output pipe is you, but you are blocked on the input
+ pipe. */
+
+extern FILE *pex_write_input (struct pex_obj *obj, int binary);
+
+/* Return a stream for a temporary file to pass to the first program
+ in the pipeline as input. The file name is chosen as for pex_run.
+ pex_run closes the file automatically; don't close it yourself. */
+
+extern FILE *pex_input_file (struct pex_obj *obj, int flags,
+ const char *in_name);
+
+/* Return a stream for a pipe connected to the standard input of the
+ first program in the pipeline. You must have passed
+ `PEX_USE_PIPES' to `pex_init'. Close the returned stream
+ yourself. */
+
+extern FILE *pex_input_pipe (struct pex_obj *obj, int binary);
+
/* Read the standard output of the last program to be executed.
pex_run can not be called after this. BINARY should be non-zero if
the file should be opened in binary mode; this is ignored on Unix.