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authorNick Alcock <nick.alcock@oracle.com>2020-06-09 10:27:57 +0100
committerNick Alcock <nick.alcock@oracle.com>2020-07-22 18:02:18 +0100
commitd50c08025d41b2efc70dbb384fc691f2d9632463 (patch)
treef32f5a1ea26d5cedd9d159135ea48a16aa3f4d94 /gold/sparc.cc
parent70447401740235d828c4b7b87e398eeae4801094 (diff)
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libctf, open: fix opening CTF in binaries with no symtab
This is a perfectly possible case, and half of ctf_bfdopen_ctfsect handled it fine. The other half hit a divide by zero or two before we got that far, and had no code path to load the strtab from anywhere in the absence of a symtab to point at it in any case. So, as a fallback, if there is no symtab, try loading ".strtab" explicitly by name, like we used to before we started looking for the strtab the symtab used. Of course, such a strtab is not kept hold of by BFD, so this means we have to bring back the code to possibly explicitly free the strtab that we read in. libctf/ * ctf-impl.h (struct ctf_archive_internal) <ctfi_free_strsect> New. * ctf-open-bfd.c (ctf_bfdopen_ctfsect): Explicitly open a strtab if the input has no symtab, rather than dividing by zero. Arrange to free it later via ctfi_free_ctfsect. * ctf-archive.c (ctf_new_archive_internal): Do not ctfi_free_strsect by default. (ctf_arc_close): Possibly free it here.
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