Fix "b f(std::string)" when current language is C

If you try to set a breakpoint at a function such as "b
f(std::string)", and the current language is C, the breakpoint fails
to be set, like so:

  (gdb) set language c
  break f(std::string)
  Function "f(std::string)" not defined.
  Make breakpoint pending on future shared library load? (y or [n]) n
  (gdb)

The problem is that the code in GDB that expands the std::string
typedef hits this in c-typeprint.c:

      /* If we have "typedef struct foo {. . .} bar;" do we want to
	 print it as "struct foo" or as "bar"?  Pick the latter for
	 C++, because C++ folk tend to expect things like "class5
	 *foo" rather than "struct class5 *foo".  We rather
	 arbitrarily choose to make language_minimal work in a C-like
	 way. */
      if (language == language_c || language == language_minimal)
	{
	  if (type->code () == TYPE_CODE_UNION)
	    gdb_printf (stream, "union ");
	  else if (type->code () == TYPE_CODE_STRUCT)
	    {
	      if (type->is_declared_class ())
		gdb_printf (stream, "class ");
	      else
		gdb_printf (stream, "struct ");
	    }
	  else if (type->code () == TYPE_CODE_ENUM)
	    gdb_printf (stream, "enum ");
	}

I.e., std::string is expanded to "class std::..." instead of just
"std::...", and then the "f(class std::..." symbol doesn't exist.

Fix this by making cp-support.c:inspect_type print the expanded
typedef type using the language of the symbol whose type we're
expanding the typedefs for -- in the example in question, the
"std::string" typedef symbol, which is a C++ symbol.

Use type_print_raw_options as it seems to me that in this scenario we
always want raw types, to match the real symbol names.

Adjust the gdb.cp/break-f-std-string.exp testcase to try setting a
breakpoint at "f(std::string)" in both C and C++.

Change-Id: Ib54fab4cf0fd307bfd55bf1dd5056830096a653b

2 files changed, 19 insertions, 4 deletions

diff --git a/gdb/cp-support.c b/gdb/cp-support.c
index 71c1463..807c944 100644
--- a/gdb/cp-support.c
+++ b/gdb/cp-support.c
@@ -41,6 +41,7 @@
 #include <atomic>
 #include "event-top.h"
 #include "run-on-main-thread.h"
+#include "typeprint.h"
 
 #define d_left(dc) (dc)->u.s_binary.left
 #define d_right(dc) (dc)->u.s_binary.right
@@ -229,7 +230,14 @@ inspect_type (struct demangle_parse_info *info,
 	  string_file buf;
 	  try
 	    {
-	      type_print (type, "", &buf, -1);
+	      /* Avoid using the current language.  If the language is
+		 C, and TYPE is a struct/class, the printed type is
+		 prefixed with "struct " or "class ", which we don't
+		 want when we're expanding a C++ typedef.  Print using
+		 the type symbol's language to expand a C++ typedef
+		 the C++ way even if the current language is C.  */
+	      const language_defn *lang = language_def (sym->language ());
+	      lang->print_type (type, "", &buf, -1, 0, &type_print_raw_options);
 	    }
 	  /* If type_print threw an exception, there is little point
 	     in continuing, so just bow out gracefully.  */
diff --git a/gdb/testsuite/gdb.cp/break-f-std-string.exp b/gdb/testsuite/gdb.cp/break-f-std-string.exp
index 0869912..e222bae 100644
--- a/gdb/testsuite/gdb.cp/break-f-std-string.exp
+++ b/gdb/testsuite/gdb.cp/break-f-std-string.exp
@@ -93,10 +93,17 @@ proc test {cxx11_abi} {
 	}
     }
 
-    gdb_test "break f($type)" "$srcfile, line $::decimal\\."
+    # GDB should be able to expand the std::string typedef in the
+    # function prototype using C++ logic even if the current language
+    # is C.
+    foreach_with_prefix lang {"c" "c++"} {
+	gdb_test_no_output "set language $lang"
 
-    if { $realtype != "" } {
-	gdb_test "break f($realtype)" "$srcfile, line $::decimal\\."
+	gdb_test "break f($type)" "$srcfile, line $::decimal\\."
+
+	if { $realtype != "" } {
+	    gdb_test "break f($realtype)" "$srcfile, line $::decimal\\."
+	}
     }
 }