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authorJoel Brobecker <brobecker@gnat.com>2009-03-13 01:28:05 +0000
committerJoel Brobecker <brobecker@gnat.com>2009-03-13 01:28:05 +0000
commitfacc390f025eafceabfe087e0fb241a8f2d90e32 (patch)
treede296964bd1e4dcbb4a647d948b435a46ba43866 /gdb/ada-lang.c
parent5c20fa2ae3f71e8fbbfe8aac31bb4a3f5a7449ea (diff)
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* ada-lang.c (ada_delta): Change the type of numerators and
denominators to DOUBLEST, as they may not fit into a long. (scaling_factor): Ditto.
Diffstat (limited to 'gdb/ada-lang.c')
-rw-r--r--gdb/ada-lang.c24
1 files changed, 17 insertions, 7 deletions
diff --git a/gdb/ada-lang.c b/gdb/ada-lang.c
index 0ec724f..aa5dece 100644
--- a/gdb/ada-lang.c
+++ b/gdb/ada-lang.c
@@ -9296,12 +9296,16 @@ DOUBLEST
ada_delta (struct type *type)
{
const char *encoding = fixed_type_info (type);
- long num, den;
+ DOUBLEST num, den;
- if (sscanf (encoding, "_%ld_%ld", &num, &den) < 2)
+ /* Strictly speaking, num and den are encoded as integer. However,
+ they may not fit into a long, and they will have to be converted
+ to DOUBLEST anyway. So scan them as DOUBLEST. */
+ if (sscanf (encoding, "_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT,
+ &num, &den) < 2)
return -1.0;
else
- return (DOUBLEST) num / (DOUBLEST) den;
+ return num / den;
}
/* Assuming that ada_is_fixed_point_type (TYPE), return the scaling
@@ -9311,17 +9315,23 @@ static DOUBLEST
scaling_factor (struct type *type)
{
const char *encoding = fixed_type_info (type);
- unsigned long num0, den0, num1, den1;
+ DOUBLEST num0, den0, num1, den1;
int n;
- n = sscanf (encoding, "_%lu_%lu_%lu_%lu", &num0, &den0, &num1, &den1);
+ /* Strictly speaking, num's and den's are encoded as integer. However,
+ they may not fit into a long, and they will have to be converted
+ to DOUBLEST anyway. So scan them as DOUBLEST. */
+ n = sscanf (encoding,
+ "_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT
+ "_%" DOUBLEST_SCAN_FORMAT "_%" DOUBLEST_SCAN_FORMAT,
+ &num0, &den0, &num1, &den1);
if (n < 2)
return 1.0;
else if (n == 4)
- return (DOUBLEST) num1 / (DOUBLEST) den1;
+ return num1 / den1;
else
- return (DOUBLEST) num0 / (DOUBLEST) den0;
+ return num0 / den0;
}