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Diffstat (limited to 'gcc/tree-data-ref.c')
| -rw-r--r-- | gcc/tree-data-ref.c | 20 |
1 files changed, 15 insertions, 5 deletions
diff --git a/gcc/tree-data-ref.c b/gcc/tree-data-ref.c index 3c88346..718059f 100644 --- a/gcc/tree-data-ref.c +++ b/gcc/tree-data-ref.c @@ -513,11 +513,12 @@ estimate_niter_from_size_of_data (struct loop *loop, array_size = TYPE_SIZE (TREE_TYPE (opnd0)); element_size = TYPE_SIZE (TREE_TYPE (TREE_TYPE (opnd0))); if (array_size == NULL_TREE - || element_size == NULL_TREE) + || TREE_CODE (array_size) != INTEGER_CST + || TREE_CODE (element_size) != INTEGER_CST) return; data_size = fold (build2 (EXACT_DIV_EXPR, integer_type_node, - array_size, element_size)); + array_size, element_size)); if (init != NULL_TREE && step != NULL_TREE @@ -1435,12 +1436,21 @@ analyze_subscript_affine_affine (tree chrec_a, if (j1 > 0) { - int last_conflict; + int last_conflict, min_multiple; tau1 = MAX (tau1, CEIL (-j0, j1)); tau2 = MIN (tau2, FLOOR_DIV (niter - j0, j1)); - x0 = (i1 * tau1 + i0) % i1; - y0 = (j1 * tau1 + j0) % j1; + x0 = i1 * tau1 + i0; + y0 = j1 * tau1 + j0; + + /* At this point (x0, y0) is one of the + solutions to the Diophantine equation. The + next step has to compute the smallest + positive solution: the first conflicts. */ + min_multiple = MIN (x0 / i1, y0 / j1); + x0 -= i1 * min_multiple; + y0 -= j1 * min_multiple; + tau1 = (x0 - i0)/i1; last_conflict = tau2 - tau1; |