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authorPatrick Palka <ppalka@redhat.com>2022-04-01 14:56:20 -0400
committerPatrick Palka <ppalka@redhat.com>2022-04-01 14:56:20 -0400
commit95533fe4f014c10dd18de649927668aba6117daf (patch)
tree0b223d19b1c4bb27635bbea774bc99652fe3f9f0
parente9ea121da7d0c6ee7214ca74f861fa5f4bc16913 (diff)
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c++: deducing from class type of NTTP [PR105110]
Here when attempting to deduce T in the NTTP type A<T> from the argument type 'const A<int>', we give up due to the const: types ‘A<T>’ and ‘const A<int>’ have incompatible cv-qualifiers But since the type of an NTTP cannot be cv-qualified, it seems natural to ignore cv-qualifiers on the argument type before attempting to unify the two types. PR c++/105110 gcc/cp/ChangeLog: * pt.cc (unify) <case TEMPLATE_PARM_INDEX>: Drop cv-quals from the argument type of an NTTP before deducing from it. gcc/testsuite/ChangeLog: * g++.dg/cpp2a/nontype-class52.C: New test.
-rw-r--r--gcc/cp/pt.cc5
-rw-r--r--gcc/testsuite/g++.dg/cpp2a/nontype-class52.C13
2 files changed, 16 insertions, 2 deletions
diff --git a/gcc/cp/pt.cc b/gcc/cp/pt.cc
index bdba5cf..75ed9a3 100644
--- a/gcc/cp/pt.cc
+++ b/gcc/cp/pt.cc
@@ -24266,8 +24266,9 @@ unify (tree tparms, tree targs, tree parm, tree arg, int strict,
&& !(strict & UNIFY_ALLOW_INTEGER)
&& TEMPLATE_PARM_LEVEL (parm) <= TMPL_ARGS_DEPTH (targs))
{
- /* Deduce it from the non-type argument. */
- tree atype = TREE_TYPE (arg);
+ /* Deduce it from the non-type argument. As above, ignore
+ top-level quals here too. */
+ tree atype = cv_unqualified (TREE_TYPE (arg));
RECUR_AND_CHECK_FAILURE (tparms, targs,
tparm, atype,
UNIFY_ALLOW_NONE, explain_p);
diff --git a/gcc/testsuite/g++.dg/cpp2a/nontype-class52.C b/gcc/testsuite/g++.dg/cpp2a/nontype-class52.C
new file mode 100644
index 0000000..5616337
--- /dev/null
+++ b/gcc/testsuite/g++.dg/cpp2a/nontype-class52.C
@@ -0,0 +1,13 @@
+// PR c++/105110
+// { dg-do compile { target c++20 } }
+
+template<class> struct A { };
+
+template<auto> struct B { };
+
+template<class T, A<T> V> void f(B<V>);
+
+int main() {
+ constexpr A<int> a;
+ f(B<a>{});
+}