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authorAndrew Pinski <apinski@marvell.com>2023-09-17 11:20:36 -0700
committerAndrew Pinski <apinski@marvell.com>2023-09-18 13:45:35 -0700
commit7ea501d3ea698e1c845fb61e3487f4cd949e6253 (patch)
tree5abc352ce405662ffebe81270253815ffb8a889c
parent951d3c191d01440ad54415f683437770b0c957e4 (diff)
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MATCH: Make zero_one_valued_p non-recursive fully
So it turns out VN can't handle any kind of recursion for match. In this case we have `b = a & -1` and we try to match a as being zero_one_valued_p and VN returns b as being the value and we just go into an infinite loop at this point. OK? Bootstrapped and tested on x86_64-linux-gnu with no regressions. Note genmatch should warn (or error out) if this gets detected so I filed PR 111446 which I will be looking into next week or the week after so we don't run into this issue again. PR tree-optimization/111442 gcc/ChangeLog: * match.pd (zero_one_valued_p): Have the bit_and match not be recursive. gcc/testsuite/ChangeLog: * gcc.c-torture/compile/pr111442-1.c: New test.
-rw-r--r--gcc/match.pd5
-rw-r--r--gcc/testsuite/gcc.c-torture/compile/pr111442-1.c13
2 files changed, 17 insertions, 1 deletions
diff --git a/gcc/match.pd b/gcc/match.pd
index a405c9f..bef513a 100644
--- a/gcc/match.pd
+++ b/gcc/match.pd
@@ -2183,8 +2183,11 @@ DEFINE_INT_AND_FLOAT_ROUND_FN (RINT)
/* (a&1) is always [0,1] too. This is useful again when
the range is not known. */
+/* Note this can't be recursive due to VN handling of equivalents,
+ VN and would cause an infinite recursion. */
(match zero_one_valued_p
- (bit_and:c@0 @1 zero_one_valued_p))
+ (bit_and:c@0 @1 integer_onep)
+ (if (INTEGRAL_TYPE_P (type))))
/* A conversion from an zero_one_valued_p is still a [0,1].
This is useful when the range of a variable is not known */
diff --git a/gcc/testsuite/gcc.c-torture/compile/pr111442-1.c b/gcc/testsuite/gcc.c-torture/compile/pr111442-1.c
new file mode 100644
index 0000000..5814ee9
--- /dev/null
+++ b/gcc/testsuite/gcc.c-torture/compile/pr111442-1.c
@@ -0,0 +1,13 @@
+
+int *a, b;
+int main() {
+ int d = 1, e;
+ if (d)
+ e = a ? 0 % 0 : 0;
+ if (d)
+ a = &d;
+ d = -1;
+ b = d & e;
+ b = 2 * e ^ 1;
+ return 0;
+}