libctf: remove is-BTF dead-reckoning

Before now we've been trying to remember whether a CTF dict is representable
as BTF via tracking when changes are made that make it non-BTF.  This is a
lot of work for nothing: the existence of write-time type suppression means
that even if you add non-BTF type kinds, you might well decide to suppress
them at writeout time, making the resulting dict pure BTF after all.

Rip this whole thing out.

(Also use some of the new macros we just added.)

1 files changed, 0 insertions, 9 deletions

diff --git a/libctf/ctf-open.c b/libctf/ctf-open.c
index 802e258..d6e8bae 100644
--- a/libctf/ctf-open.c
+++ b/libctf/ctf-open.c
@@ -659,14 +659,6 @@ init_static_types (ctf_dict_t *fp, ctf_header_t *cth)
       pop[kind]++;
     }
 
-  /* CTF-only kinds: this dict cannot be written as BTF.  (There may be further
-     reasons why this dict cannot be written as BTF that we haven't discovered
-     yet.)  */
-
-  if (pop[CTF_K_FLOAT] > 0 || pop[CTF_K_SLICE] > 0 || pop[CTF_K_BIG] > 0
-      || pop[CTF_K_CONFLICTING] > 0)
-    fp->ctf_is_btf = 0;
-
   if (child)
     {
       ctf_dprintf ("CTF dict %p is a child\n", (void *) fp);
@@ -2062,7 +2054,6 @@ ctf_bufopen (const ctf_sect_t *ctfsect, const ctf_sect_t *symsect,
   if (version == IS_BTF)
     hp->cth_version = CTF_VERSION_4;
 
-  fp->ctf_is_btf = 1;
   fp->ctf_version = hp->cth_version;
   fp->ctf_dictops = &ctf_dictops[ctf_version];