Turn parse_language into a method

This changes parse_language into a method of parser_state.  This patch
was written by a script.

gdb/ChangeLog
2019-04-04  Tom Tromey  <tom@tromey.com>

	* rust-exp.y: Replace "parse_language" with method call.
	* p-exp.y:
	(yylex): Replace "parse_language" with method call.
	* m2-exp.y:
	(yylex): Replace "parse_language" with method call.
	* go-exp.y (classify_name): Replace "parse_language" with method
	call.
	* f-exp.y (yylex): Replace "parse_language" with method call.
	* d-exp.y (lex_one_token): Replace "parse_language" with method
	call.
	* c-exp.y:
	(lex_one_token, classify_name, yylex): Replace "parse_language"
	with method call.
	* ada-exp.y (find_primitive_type, type_char)
	(type_system_address): Replace "parse_language" with method call.

1 files changed, 7 insertions, 2 deletions

diff --git a/gdb/parser-defs.h b/gdb/parser-defs.h
index 1aa5f1f..8fcbca3 100644
--- a/gdb/parser-defs.h
+++ b/gdb/parser-defs.h
@@ -32,8 +32,6 @@ struct internalvar;
 
 extern int parser_debug;
 
-#define parse_language(ps) ((ps)->expout->language_defn)
-
 struct parser_state
 {
   /* Constructor.  LANG is the language used to parse the expression.
@@ -55,6 +53,13 @@ struct parser_state
     return expout->gdbarch;
   }
 
+  /* Return the language that was passed to the constructor.  */
+
+  const struct language_defn *language ()
+  {
+    return expout->language_defn;
+  }
+
   /* The size of the expression above.  */
 
   size_t expout_size;