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# std::experimental::filesystem::path::root_name

From cppreference.com
< cpp‎ | experimental‎ | fs‎ | path

path root_name() const; |  | (filesystem TS)

Returns the root name of the path. If the path does not include root name, returns path().

### [edit] Parameters

(none)

### [edit] Return value

The root name of the path.

### [edit] Exceptions

(none)

### [edit] Example

Run this code

    #include <iostream>
    #include <experimental/filesystem>
    namespace fs = std::experimental::filesystem;

    int main()
    {
        std::cout << "Current root name is: " << fs::current_path().root_name() << '\n';
    }

Possible output:

    Current root name is: "C:"

### [edit] See also

root_directory | returns the root directory of the path, if present (public member function) [edit]
root_path | returns the root path of the path, if present (public member function) [edit]

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