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# std::unordered_set::begin, std::unordered_set::cbegin

From cppreference.com
< cpp‎ | container‎ | unordered set

[edit template]

iterator begin(); |  | (since C++11)
const_iterator begin() const; |  | (since C++11)
const_iterator cbegin() const; |  | (since C++11)

Returns an iterator to the first element of the container.

If the container is empty, the returned iterator will be equal to end().

### [edit] Parameters

(none)

### [edit] Return value

Iterator to the first element

### [edit] Exceptions

`noexcept` specification:
noexcept

### [edit] Complexity

Constant

### [edit] Example

Run this code

    #include <iostream>
    #include <unordered_set>

    struct Point { double x, y; };

    int main() {
        Point pts[3] = { {1, 0}, {2, 0}, {3, 0} };

        //points is a set containing the addresses of points
        std::unordered_set<Point *> points = { pts, pts + 1, pts + 2 };

        //Change each y-coordinate of (i, 0) from 0 into i^2 and print the point
        for(auto iter = points.begin(); iter != points.end(); ++iter){
            (*iter)->y = ((*iter)->x) * ((*iter)->x); //iter is a pointer-to-Point*
            std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") ";
        }
        std::cout << '\n';

        //Now using the range-based for loop, we increase each y-coordinate by 10
        for(Point * i : points) {
            i->y += 10;
            std::cout << "(" << i->x << ", " << i->y << ") ";
        }
    }

Possible output:

    (3, 9) (1, 1) (2, 4)
    (3, 19) (1, 11) (2, 14)

### [edit] See also

end cend | returns an iterator to the end (public member function) [edit]

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