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# std::make_signed

From cppreference.com
< cpp‎ | types

Defined in header `<type_traits>` |  |
template< class T > struct make_signed; |  | (since C++11)

If `T` is an integral (except bool) or enumeration type, provides the member typedef `type` which is the signed integer type corresponding to `T`, with the same cv-qualifiers.

Otherwise, the behavior is undefined.

### [edit] Member types

Name | Definition
`type` | the signed integer type corresponding to `T`

### [edit] Helper types

template< class T > using make_signed_t = typename make_signed<T>::type; |  | (since C++14)

### [edit] Example

Run this code

    #include <iostream>
    #include <type_traits>

    int main() {
        typedef std::make_signed<char>::type char_type;
        typedef std::make_signed<int>::type int_type;
        typedef std::make_signed<volatile long>::type long_type;

        bool ok1 = std::is_same<char_type, signed char>::value;
        bool ok2 = std::is_same<int_type, signed int>::value;
        bool ok3 = std::is_same<long_type, volatile signed long>::value;

        std::cout << std::boolalpha
        << "char_type is 'signed char'?          : " << ok1 << '\n'
        << "int_type  is 'signed int'?           : " << ok2 << '\n'
        << "long_type is 'volatile signed long'? : " << ok3 << '\n';
    }

Output:

    char_type is 'signed char'?          : true
    int_type  is 'signed int'?           : true
    long_type is 'volatile signed long'? : true

### [edit] See also

is_signed (C++11) | checks if a type is signed arithmetic type (class template) [edit]
is_unsigned (C++11) | checks if a type is unsigned arithmetic type (class template) [edit]
make_unsigned (C++11) | makes the given integral type unsigned (class template) [edit]

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