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# std::move_backward

From cppreference.com
< cpp‎ | algorithm

Defined in header `<algorithm>` |  |
template< class BidirIt1, class BidirIt2 > BidirIt2 move_backward( BidirIt1 first, BidirIt1 last, BidirIt2 d_last ); |  | (since C++11)

Moves the elements from the range `[first, last)`, to another range ending at `d_last`. The elements are moved in reverse order (the last element is moved first), but their relative order is preserved.

The behavior is undefined if `d_last` is within `(first, last]`. std::move must be used instead of `std::move_backward` in that case.

### [edit] Parameters

first, last | - | the range of the elements to move
d_last | - | end of the destination range
Type requirements
- `BidirIt1, BidirIt2` must meet the requirements of `BidirectionalIterator`.

### [edit] Return value

Iterator in the destination range, pointing at the last element moved.

### [edit] Complexity

Exactly `last - first` move assignments.

### [edit] Possible implementation

    template< class BidirIt1, class BidirIt2 >
    BidirIt2 move_backward(BidirIt1 first,
                                         BidirIt1 last,
                                         BidirIt2 d_last)
    {
        while (first != last) {
            *(--d_last) = std::move(*(--last));
        }
        return d_last;
    }

### [edit] Notes

When moving overlapping ranges, `std::move` is appropriate when moving to the left (beginning of the destination range is outside the source range) while `std::move_backward` is appropriate when moving to the right (end of the destination range is outside the source range).

### [edit] Example

Run this code

    #include <algorithm>
    #include <vector>
    #include <string>
    #include <iostream>

    int main()
    {
        std::vector<std::string> src{"foo", "bar", "baz"};
        std::vector<std::string> dest(src.size());

        std::cout << "src: ";
        for (const auto &s : src)
        {
            std::cout << s << ' ';
        }
        std::cout << "\ndest: ";
        for (const auto &s : dest)
        {
            std::cout << s << ' ';
        }
        std::cout << '\n';

        std::move_backward(src.begin(), src.end(), dest.end());

        std::cout << "src: ";
        for (const auto &s : src)
        {
            std::cout << s << ' ';
        }
        std::cout << "\ndest: ";
        for (const auto &s : dest)
        {
            std::cout << s << ' ';
        }
        std::cout << '\n';
    }

Output:

    src: foo bar baz
    dest:
    src:
    dest: foo bar baz

### [edit] See also

move (C++11) | moves a range of elements to a new location (function template) [edit]

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