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# std::is_bind_expression

From cppreference.com
< cpp‎ | utility‎ | functional

Defined in header `<functional>` |  |
template< class T > struct is_bind_expression; |  | (since C++11)

If `T` is the type produced by a call to std::bind, this template provides the member constant value equal true. For any other type, `value` is false.

This template may be specialized for a user-defined type which should be treated by std::bind as if it was the type of a bind subexpression: when a bind-generated function object is invoked, a bound argument of this type will be invoked as a function object and will be given all the unbound arguments passed to the bind-generated object.

## Inherited from std::integral_constant

### Member constants

value [static] | true if `T` is a function object generated by std::bind, false otherwise (public static member constant)

### Member functions

operator bool | converts the object to bool, returns `value` (public member function)

### Member types

Type | Definition
`value_type` | `bool`
`type` | std::integral_constant<bool, value>

### [edit] Example

Run this code

    #include <iostream>
    #include <type_traits>
    #include <functional>

    struct MyBind {
        typedef int result_type;
        int operator()(int a, int b) const { return a + b; }
    };

    namespace std {
        template<>
        struct is_bind_expression<MyBind> : public true_type {};
    }

    int f(int n1, int n2)
    {
        return n1+n2;
    }

    int main()
    {
        // as if bind(f, bind(MyBind::operator(), _1, _2), 2)
        auto b = std::bind(f, MyBind(), 2);

        std::cout << "Adding 2 to the sum of 10 and 11 gives " << b(10, 11) << '\n';
    }

Output:

    Adding 2 to the sum of 10 and 11 gives 23

### [edit] See also

bind (C++11) | binds one or more arguments to a function object (function template) [edit]

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