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# std::set::operator=

From cppreference.com
< cpp‎ | container‎ | set

set& operator=( const set& other ); | (1) |
set& operator=( set&& other ); | (2) | (since C++11)
set& operator=( std::initializer_list<value_type> ilist ); | (3) | (since C++11)

Replaces the contents of the container.

1) Copy assignment operator. Replaces the contents with a copy of the contents of `other`.If std::allocator_traits<allocator_type>::propagate_on_container_copy_assignment() is true, the target allocator is replaced by a copy of the source allocator. If the target and the source allocators do not compare equal, the target (*this) allocator is used to deallocate the memory, then `other`'s allocator is used to allocate it before copying the elements.(since C++11)
2) Move assignment operator. Replaces the contents with those of `other` using move semantics (i.e. the data in `other` is moved from `other` into this container). `other` is in a valid but unspecified state afterwards. If std::allocator_traits<allocator_type>::propagate_on_container_move_assignment() is true, the target allocator is replaced by a copy of the source allocator. If it is false and the source and the taget allocators do not compare equal, the target cannot take ownership of the source memory and must move-assign each element individually, allocating additional memory using its own allocator as needed.(since C++11)
3) Replaces the contents with those identified by initializer list `ilist`.

### [edit] Parameters

other | - | another container to use as data source
ilist | - | initializer list to use as data source

### [edit] Return value

*this

### [edit] Complexity

1) Linear in the size of the `other`.
2) Constant.
3) Linear in the size of `ilist`.

### [edit] Example

[edit]

The following code uses `` to assign one std::set to another:

Run this code

    #include <set>
    #include <iostream>

    void display_sizes(const std::set<int> &nums1,
                       const std::set<int> &nums2,
                       const std::set<int> &nums3)
    {
        std::cout << "nums1: " << nums1.size()
                  << " nums2: " << nums2.size()
                  << " nums3: " << nums3.size() << '\n';
    }

    int main()
    {
        std::set<int> nums1 {3, 1, 4, 6, 5, 9};
        std::set<int> nums2;
        std::set<int> nums3;

        std::cout << "Initially:\n";
        display_sizes(nums1, nums2, nums3);

        // copy assignment copies data from nums1 to nums2
        nums2 = nums1;

        std::cout << "After assigment:\n";
        display_sizes(nums1, nums2, nums3);

        // move assignment moves data from nums1 to nums3,
        // modifying both nums1 and nums3
        nums3 = std::move(nums1);

        std::cout << "After move assigment:\n";
        display_sizes(nums1, nums2, nums3);
    }

Output:

    Initially:
    nums1: 6 nums2: 0 nums3: 0
    After assigment:
    nums1: 6 nums2: 6 nums3: 0
    After move assigment:
    nums1: 0 nums2: 6 nums3: 6

### [edit] See also

(constructor) | constructs the `set` (public member function) [edit]

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