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# std::minmax

From cppreference.com
< cpp‎ | algorithm

Defined in header `<algorithm>` |  |
template< class T > std::pair<const T&,const T&> minmax( const T& a, const T& b ); | (1) | (since C++11)
template< class T, class Compare > std::pair<const T&,const T&> minmax( const T& a, const T& b, Compare comp ); | (2) | (since C++11)
template< class T > std::pair<T,T> minmax( std::initializer_list<T> ilist); | (3) | (since C++11)
template< class T, class Compare > std::pair<T,T> minmax( std::initializer_list<T> ilist, Compare comp ); | (4) | (since C++11)

Returns the lowest and the greatest of the given values.

1-2) Returns the smaller and the greater of `a` and `b`.
3-4) Returns the smallest and the greatest of the values in initializer list `ilist`.

The (1,3) versions use operator< to compare the values, whereas the (2,4) versions use the given comparison function `comp`.

### [edit] Parameters

a, b | - | the values to compare
ilist | - | initializer list with the values to compare
comp | - | comparison function object (i.e. an object that satisfies the requirements of `Compare`) which returns ​true if if `a` is less than `b`. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function object must not modify the objects passed to it. The types Type1 and Type2 must be such that an object of type T can be implicitly converted to both of them. ​
Type requirements
- `T` must meet the requirements of `LessThanComparable`. for the overloads (1) and (3)
- `T` must meet the requirements of `CopyConstructible`. for the overloads (3) and (4)

### [edit] Return value

1-2) Returns the result of std::make_pair(a, b) if `a<b` or if `a` is equivalent to `b`. Returns the result of std::make_pair(b, a) if `b<a`.
3-4) A pair with the smallest value in `ilist` as the first element and the greatest as the second. If several elements are equivalent to the smallest, the leftmost such element is returned. If several elements are equivalent to the largest, the rightmost such element is returned.

### [edit] Complexity

1-2) Constant
3-4) Linear in `ilist.size()`

### [edit] Possible implementation

First version
    template<class T>
    std::pair<const T&, const T&> minmax(const T& a, const T& b)
    {
        return (b < a) ? std::make_pair(b, a)
                       : std::make_pair(a, b);
    }
Second version
    template<class T, class Compare>
    std::pair<const T&, const T&> minmax(const T& a, const T& b, Compare comp)
    {
        return comp(b, a) ? std::make_pair(b, a)
                          : std::make_pair(a, b);
    }
Third version
    template< class T >
    std::pair<T, T> minmax( std::initializer_list<T> ilist)
    {
        auto p = std::minmax_element(ilist.begin(), ilist.end());
        return std::make_pair(*p.first, *p.second);
    }
Fourth version
    template< class T, class Compare >
    std::pair<T, T> minmax( std::initializer_list<T> ilist, Compare comp )
    {
        auto p = std::minmax_element(ilist.begin(), ilist.end(), comp);
        return std::make_pair(*p.first, *p.second);
    }

### [edit] Example

Run this code

    #include <algorithm>
    #include <iostream>
    #include <vector>
    #include <cstdlib>
    #include <ctime>

    int main()
    {
        std::vector<int> v {3, 1, 4, 1, 5, 9, 2, 6};
        std::srand(std::time(0));
        std::pair<int, int> bounds = std::minmax(std::rand() % v.size(),
                                                 std::rand() % v.size());

        std::cout << "v[" << bounds.first << "," << bounds.second << "]: ";
        for (int i = bounds.first; i < bounds.second; ++i) {
            std::cout << v[i] << ' ';
        }
        std::cout << '\n';
    }

Possible output:

    v[2,7]: 4 1 5 9 2

### [edit] See also

min | returns the smaller of two elements (function template) [edit]
max | returns the larger of two elements (function template) [edit]

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