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# div, ldiv, lldiv, imaxdiv

From cppreference.com
< c‎ | numeric‎ | math

Defined in header `<stdlib.h>` |  |
div_t div( int x, int y ); | (1) |
ldiv_t ldiv( long x, long y ); | (2) |
lldiv_t lldiv( long long x, long long y ); | (3) | (since C99)
Defined in header `<inttypes.h>` |  |
imaxdiv_t imaxdiv( intmax_t x, intmax_t y ); | (4) | (since C99)

Computes both the quotient and the remainder of the division of the numerator `x` by the denominator `y`

Computes quotient and remainder simultaneously. The quotient is the algebraic quotient with any fractional part discarded (truncated towards zero). The remainder is such that quot * y + rem == x. | (until C99)
Computes the quotient (the result of the expression x/y) and remainder (the result of the expression x%y) simultaneously. | (since C99)

### [edit] Parameters

x, y | - | integer values

### [edit] Return value

If both the remainder and the quotient can be represented as objects of the corresponding type (int, long, long long, imaxdiv_t, respectively), returns both as an object of type `div_t`, `ldiv_t`, `ldiv_t`, `imaxdiv_t` defined as follows:

# div_t

    struct div_t { int quot; int rem; };

or

    struct div_t { int rem; int quot; };

# ldiv_t

    struct ldiv_t { long quot; long rem; };

or

    struct ldiv_t { long rem; long quot; };

# lldiv_t

    struct lldiv_t { long long quot; long long rem; };

or

    struct lldiv_t { long long rem; long long quot; };

# imaxdiv_t

    struct imaxdiv_t { intmax_t quot; intmax_t rem; };

or

    struct imaxdiv_t { intmax_t rem; intmax_t quot; };

If either the remainder or the quotient cannot be represented, the behavior is undefined.

### [edit] Notes

Until C99, the rounding direction of the quotient and the sign of the remainder in the built-in division and remainder operators was implementation-defined if either of the operands was negative, but it was well-defined in `div` and `ldiv`.

On many platforms, a single CPU instruction obtains both the quotient and the remainder, and this function may leverage that, although compilers are generally able to merge nearby / and % where suitable.

### [edit] Example

Run this code

    #include <stdio.h>
    #include <math.h>
    #include <stdlib.h>

    // demo only: does not check for buffer overflow
    void itoa(int n, int base, char* buf)
    {
        div_t dv = {.quot = n};
        char* p = buf;
        do {
            dv = div(dv.quot, base);
            *p++ = "0123456789abcdef"[abs(dv.rem)];
        } while(dv.quot);
        if(n<0) *p++ = '-';
        *p-- = '\0';
        while(buf < p) { char c = *p; *p-- = *buf; *buf++ = c; } // reverse
    }

    int main(void)
    {
        char buf[100];
        itoa(12346, 10, buf);
        printf("%s\n", buf);
        itoa(-12346, 10, buf);
        printf("%s\n", buf);
        itoa(65535, 16, buf);
        printf("%s\n", buf);
    }

Output:

    12346
    -12346
    ffff

### [edit] See also

fmod fmodf fmodl (C99)(C99) | computes remainder of the floating-point division operation (function) [edit]
remainder remainderf remainderl (C99)(C99)(C99) | computes signed remainder of the floating-point division operation (function) [edit]
remquo remquof remquol (C99)(C99)(C99) | computes signed remainder as well as the three last bits of the division operation (function) [edit]
C++ documentation for div

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