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# std::showbase, std::noshowbase

From cppreference.com
< cpp‎ | io‎ | manip

Defined in header `<ios>` |  |
std::ios_base& showbase( std::ios_base& str ); | (1) |
std::ios_base& noshowbase( std::ios_base& str ); | (2) |

1) enables the `showbase` flag in the stream `str` as if by calling str.setf(std::ios_base::showbase)

2) disables the `showbase` flag in the stream `str` as if by calling str.unsetf(std::ios_base::showbase)

This is an I/O manipulator, it may be called with an expression such as out << std::showbase for any `out` of type std::basic_ostream or with an expression such as in >> std::showbase for any `in` of type std::basic_istream.

### [edit] Parameters

str | - | reference to I/O stream

### [edit] Return value

`str` (reference to the stream after manipulation)

### [edit] Example

Run this code

    #include <sstream>
    #include <locale>
    #include <iostream>
    #include <iomanip>
    int main()
    {
        // showbase affects the output of octals and hexadecimals
        std::cout << std::hex
                  << "showbase: " << std::showbase << 42 << '\n'
                  << "noshowbase: " << std::noshowbase << 42 << '\n';

        // and both input and output of monetary values
        std::locale::global(std::locale("en_US.utf8"));
        long double val = 0;
        std::istringstream is("3.14");
        is >> std::showbase >> std::get_money(val);
        std::cout << "With showbase, parsing 3.14 as money gives " << val << '\n';
        is.seekg(0);
        is >> std::noshowbase >> std::get_money(val);
        std::cout << "Without showbase, parsing 3.14 as money gives " << val << '\n';
    }

Output:

    showbase: 0x2a
    noshowbase: 2a
    With showbase, parsing 3.14 as money gives 0
    Without showbase, parsing 3.14 as money gives 314

### [edit] See also

resetiosflags | clears the specified ios_base flags (function) [edit]
setiosflags | sets the specified ios_base flags (function) [edit]

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