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# std::experimental::filesystem::path::root_directory

From cppreference.com
< cpp‎ | experimental‎ | fs‎ | path

path root_directory() const; |  | (filesystem TS)

Returns the root directory of the path. If the path does not include root name, returns path().

### [edit] Parameters

(none)

### [edit] Return value

The root directory of the path.

### [edit] Exceptions

(none)

### [edit] Example

Run this code

    #include <iostream>
    #include <experimental/filesystem>
    namespace fs = std::experimental::filesystem;

    int main()
    {
        fs::path p = fs::current_path();

        std::cout << "The current path " << p << " decomposes into:\n"
                  << "root name " << p.root_name() << '\n'
                  << "root directory " << p.root_directory() << '\n'
                  << "relative path " << p.relative_path() << '\n';
    }

Possible output:

    The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:
    root name "C:"
    root directory "\"
    relative path "Users\abcdef\Local Settings\temp"

### [edit] See also

root_name | returns the root-name of the path, if present (public member function) [edit]
root_path | returns the root path of the path, if present (public member function) [edit]

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